Originally Posted by
Kybuckhunter
God was never used in this argument. Just a story that was like the one from the bible. If you want to make it out like I was dishonoring God then you lie.
I have not lied once.
"You told me personally how "you" feel they are unsafe"....this part is true but there is zero facts to back this up. Like you told me "people put their own spin on things" and that's all you did. Zero facts.
Here is a part of a crossbow article I read just a few minutes ago about range...it was in this months North American Whitetail.....
"The higher draw weight of a crossbow in necessary because it has a much shorter power stroke. The shorter power stroke means that less kinetic energy is being stored in the arrow when shot. Therefore, even with the heavier draw weight, the arrow flight and speed from a crossbow are equal to or less than that of a vertical bow; and regardless of the speed, a crossbow arrow will always drop faster than a vertical bow.
Sound just like what I said and you argue against doesn't it Mr. Engineer. I know you will say it's a lie but why would they make it sound worse for the xbow if it's a pro xbow piece. It also stated that shots over 40 yards are taboo by ethical xbow hunters because of the rapid loss of speed. Pick up a copy and read it yourself.
I asked you specifically if you had a bolt and arrow wieghing the same with the same drag, same fletch would the bolt loose KE and speed faster. You said yes. Remember. You then said there is no way both could have the same drag. This is correct, if that was the case, a set of arrows would all loose energy different.
Ok, lets start there. Do you agree with these equations? If you do agree, these are the basics for Newtons law. These are the basics and start for bernoulli's equation and fluid and gas dynamics.
KE=mv^2
V=Vo+accT
Acc=F/m
F=d/dt*(mv)
Drag Force Equation F = 0.5 C ρA V2
Notation
(ft=feet, g=gram, hr=hour, kg=kilogram, lb=Pound (force), m=meter, N=Newton, s=second)
Our calculation allows you to use a variety of units with all of the conversions completed internally. The units below are consistent units for the drag force equation.
Acc=Acceleration (m/s^2 or f/s^2)
A = Reference area as (see figures above), m2.
C = Drag coefficient (see figures above), unitless.
F = Drag force, N.
V = Velocity, m/s.
ρ = Density of fluid (liquid or gas), kg/m3.
Acceleration is a function of the sum of drag coef. of both air of an arrow in flight and arrow itself. In other words, its negative, it never gains speed after it leaves the string. Acc is positive as the Fstring is pushing on the arrow or bolt until it release that arrow or bolt. If both projectiles have the same drag as shown with the Fd (force of drag), it is phsically impossible for the bolt to drop quicker. Unless in the article the bolt is heavier, fatter diameter, fatter head, larger fletch (i.e. more drag). And it could be. The only thing that could get the bolt to drop faster is gravity due to more wieght or more drag.
So in the article did they claim to have the same wieght, same diameter shaft, same fletch same point? Its that simple. Work with me. Does it specify?
I promise, I will not be rude, I will not call you dumb, I will treat you with respect, I will work out this problem and prove to you with elementary math and well known and accepted physics. Just work with me. What makes this arthor so much more an authority on this? We as humans don't have to be sheep, we can figure out stuff for ourselves.