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Old 11-16-2009 | 07:43 PM
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Big Z
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Default Gyroscopic drift: Simplified?

So, I'm trying to understand the behavior of gyroscopes and how they apply to bullets to explain drift. The obsolete "log rolling on water" theory just isn't cutting my curiosity. Now, tell me if I have this right in a simplified manner:

Rotating objects experience a push 90 degrees (in the direction of rotation) from where the force is applied. So, since bullets are dropping, the greatest force they are encountering is underneath them (dropping=hitting the air, or rather a downward acceleration implies the same). A right-twist bullet will then experience a drift as if it were being pushed from the left (which is 90 degrees from bottom of the bullet in the direction of rotation).

Do I have this understood properly in a manner, simple as it may be?
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