ORIGINAL: OHbowhntr
ORIGINAL: Transcendstime
Like this:
C being the distance from the stand the arrow must travel to a target
a= ground distance
b= height distance
c^2 = a^2 + b^2 ... formula to get the distance in a hypotenuse
SO.....
c^2 = 30^2 + 15^2
c^2= 900+ 225
1125= c^2
C=√1125
So your toal distance from 30 yards @ 15 ft high to target would be....
33.54 yrds
What Valor said!!! Actually, your MATH is WRONG because you used the wrong units. You FAILED your final exam, please report to summer school!!!
TFox alluded to where the real problem comes in these equations, it's that 7yds from the base of your tree shot that is the tough one, or when your stand is on a ravine, and you are shooting 60ft down into a ravine and your rangefinder reads 36yds, but the horizontal distance may really only be 28, it's not the 25-30yd shot that's tough. For me at 14yds, my arrow hits it's hiigh point in it's ARC(when using my top 24yd pin) which is going to be about 2.5-3" above my aimed point, therefore, knowing how my bow shoots at those distances is keeps me on line for a kill by keeping my aimpoint just a tad low. But at the same time, I'm not convinced that shot will shoot exactly for 28yds either as the arrow will actually gain some velocity on a downward angle, which may shorten the distance you need to shoot the shot for, counter that with the ARC of an arrow, which may be slightly changed if that arrow picks up 8fps during it's travels, sometimes its all GUESSWORK anyhow. Shooting for what "feels" right.
The arrow will not gain enough speed in a hunting distance that one could ever notice.The uphill shot is shot the exact same way so that eliminates that from the equation,atleast at close distances.
Now in field archery shooting 80 yard shots uphill or downhill,then there might be some validity to that argument.