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Old 05-19-2008 | 03:06 PM
  #70  
Sylvan
Nontypical Buck
 
Joined: Jan 2005
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From: Upstate New York
Default RE: What arrow mass will achieve tha maximum momentum?

ORIGINAL: bigcountry

Again, I am really surprised your having so much trouble with physics and dynamics.

Why not just post the link to the work that someone else has done instead of stealing it as your own?

http://www.archery-engineering.co.za/conversions/boweffencyandvertialmass.htm
Steal it? I said it was an excerpt.

Here's the link I took it from






http://www.tipsforarchery.com/long20bow/BOW%20EFFICIENCY.php

here are some more






http://www.koniaris.com/archery/weight/






http://www.hesston.edu/ACADEMIC/FACULTY/NELSONK/PhysicsResearch/Archery/paper.htm

and one of my favorites...






http://www.goarchers.org.uk/mechanics/

They all explain basicall the same thing I've been trying to explain here. I'll give up on you though bc, I don't think you have the kind of attitude that will allow you to learn anything.Take some time and learn and spend less time telling others they don't understand. I'll bet thepublishers ofthe information I've presented here would love to be enlightened by you. I believe one of the sights has email so give it a shot and let us all know how you made out. LOL, they deserve a good laugh!


bc, please explain the effect of m on Fin the following equation.

The bow energy efficiency F = Ea/Et thus becomes:
F = (mS2/2)/((m + v)S2/2) = m/(m + v)


If you understand the math you will recognize easily that as m increases so does F. If you disagree with that you don't understand the math, if you disagree with the equation itself, you're not arguing with me your arguing with the established physics you claim to understand.
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