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Some statistical observationsonthe 2006 Bowhunting Contest:

Number of teams: 41
Number of participants: 410
Number of bucks entered: 109
Average hunter success: 0.2658 (109/410)
Average buck score: 99.7 (10864 inches/109 bucks); standard deviation 38 inches
Expected score for each team: 264 (10*.2658*99.7)

Team Rankings: (discrepancies notedin the score totals for teams 23 and 27).




Since membership on any given team is a random event (Team XX exception noted), and with hunter success at 0.265, the

Odds of a team with no bucks: One out of 22
Odds of a team with 1 buck: One out of ~6
Odds of a team with 2 bucks: One out of ~4
Odds of a team with 3 bucks: One out of ~4
Odds of a team with 4 bucks: One out of ~6
Odds of a team with 5 bucks: One out of 14
Odds of a team with 6 bucks: One out of 46
Odds of a team with 7 bucks: One out of 224
Odds of a team with 8 bucks: One out of 1650
Odds of a team with 9 bucks: One out of 20530
Odds of a team with 10 bucks: One out of 567000

Odds that this contest would have a team with 8 bucks, given 41 teams: One out of 41 (this is coincidentaltothe number of teams).

Added in edit:Another way to look atthis last stat is that if you put all thenames in a hat, and drew41 teams randomly from the 410 names, and repeated thisaction 41 times,you would expect to draw a team with8buck entries only one time. Way to go Team 17!

-fsh