![]() |
RE: Climbing trajectory
ORIGINAL: lemoyne MO Archer, If you are using a scope the bullet normally starts out at -1.5 inches crosses the line of sight at about 30yds deping on velocity and distance sighted in for"0" |
RE: Climbing trajectory
Fact: the bullet begins dropping the instant it leaves the barrel.
Fact: The only way to get a bullet shooting "flatter" is to increase the velocity. The faster it moves, the further it gets "out there" before it drops more. The difference you are talking about is determined by how high above the bore your line of sight is. In other words, an open sight is much closer to the line of the barrel than a high mounted scope. The lower the profile of the scope, the less of a "minus" figure your get at the muzzle and the less it has to "climb" (be pointed upwards) to initially reach your line of sight. Said another way, the only way a bullet "climbs" is to be pointed upwards above your line of sight. This is trure even on the fastest magnum certerfire rifleout there. |
RE: Climbing trajectory
ORIGINAL: TXFRNTLDER The reason I ponder this is because I am dead on at 50 yards then high at 100. Maybey I am back to dead on on out at 150 175? I'm not not doubting the POI prints, but it tells me that something is terribly wrong. There is NO WAY you can be "dead on" at 50 and "higher at 100" unless something is wrong. We know this, the laws of physics will not be violated. So something is wrong. Maybe your scope? |
RE: Climbing trajectory
![]() scope or irons - same principles apply. |
RE: Climbing trajectory
Great schematic UC! A picture is worth......
|
| All times are GMT -8. The time now is 11:00 PM. |
Copyright © 2026 MH Sub I, LLC dba Internet Brands. All rights reserved. Use of this site indicates your consent to the Terms of Use.