But the peep sight would have to be at a 45degree angle to the bow sight on full draw and that is not realistic.
Bruce:
For my illustration (wheter it's right or wrong....I don't know) what difference does it make......as long as it shows the line of the arrow and the line of the sight line crossing at some point in front of the shooter....and reconnecting at the intended target? I could make the sight line much less of a grade. But.....for the purposes of what I'm looking for....I don't see the point. If you can explain to me why that's important.....I'm all ears.
It's not to scale, either.
And while it was wriiten about firearms, the principiles are the same as what you are describing here.
I'm with you, here.
The arrow, as it leaves the bow, does NOT travel a straight line. It travels in a parabolic curve, whose rate of fall increases as range increases.
OK.....I'm not disagreeing with you....I just want to know why it's traveling on this curve? And....how does it do this (law?) if we've set up our bow with the arrow level? I'd like to understand this.
The arrow starts falling the instant it comes out of the bow, so we must aim the bow upwards (via our sights/line of sight/which IS a straight line) to make this curve that the arrow is traveling intersect with the staight line that our sight follows.
How's this different than what I drew? I think I'm understanding you.....but if we made the sight line parallel with the level ground........then the same thing that is in my sketch would apply....EXCEPT that we WOULD be shooting "up".
Is that what you're depicting?
And you can launch an arrow perfectly parallel to surface of the earth, it just depends where your target is.
Isn't this what I sketched?